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Re: ACL syntax with wildcards

On 27/3/2012 4:43 ÎÎ, Hallvard B Furuseth wrote:

Nick Milas wrote:

Let me re-phrase: Can we express the following three statements using
ONE ACL statement? I haven't been able to find a solution.

access to dn.subtree="ou=people,dc=example,dc=com"
filter="(ou=dept1)" attrs="attr1,attr2"
by group.exact="cn=dept1Admins,ou=Groups,dc=example,dc=com" write
[...same with other depts...]

This should work with normal OU names, but I'd feel nervous using it
since OU names involving '] ... [' would give an "ACL injection attack":

access to dn.subtree="ou=people,dc=example,dc=com"
    attrs="attr1,attr2" filter="(ou=dept*)"
by set.exact="user & ([cn=] + this/ou + [Admins,ou=Groups,dc=example,dc=com])/member" write

Hi Hallvard,

Examining your suggestion above, I think it will not work, because it gives write access to ou=dept* (that is, to *all* ou dept values) by *any* *Admins group, whereas we want xxxAdmins to only have write access to filter="(ou=deptxxx)" only.

So, in this case, only your second suggestion would work:

access to dn.subtree="ou=people,dc=example,dc=com"
    attrs="attr1,attr2" filter="(owner=*)"
    by set.exact="user & this/owner/member" write

... which requires us to define an owner attribute per entry.

Am I right?

The problem is that we cannot specify in an ACL any "expandable" wildcard (as is possible in the main <what> clause). Would such functionality be planned for the future?

Thanks and regards,