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Re: ldapmodify command question...
Looking at man page, I think I will have to run two instances of
ldapmodify. If infile.ldif is my starting ldif file, I can run:
ldapmodify -D "cn=..." -w XXX -S noexist.ldif -x -r -f infile.ldif
The -r will cause existing entries to be overwritten (which I want),
the -S will cause errors to be written to noexist.ldif and skipped. In
my case, the errors would be entries where the dn does not exist in
ldap. So, after the above, just run:
ldapmodify -D "..." -w XXX -x -a -f noexist.ldif
That effectively does what I want to achieve, right?!
On Aug 10, 2004, at 8:53 PM, Quanah Gibson-Mount wrote:
--On Tuesday, August 10, 2004 8:28 PM -0400 John Von Essen
Is it possible to do the following:
I have a couple hundred DN's in an ldif file that look like:
cn: Bob Jones
The question is some of the dn's in my ldif file are new and do not
in LDAP server (so I add them with -x -a -f). Some entries however, do
already exist in LDAP - but I want to get rid of what is currently in
LDAP and force the ADD of what is in the ldif file. The entry in ldif
might be identical to what is in LDAP, or it might be different -
way, the data in the ldif file is superior.
I suggest a single pass first, finding what ones already exist.
Delete them, then use ldapadd to add the entire file.
Principal Software Developer
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John Von Essen (firstname.lastname@example.org)
President, Essenz Consulting (www.essenz.com)
Phone: (800) 248-1736
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