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Re: ordered indexing for integers
Howard Chu writes:
> I think you misunderstood.
No, I wrote too briefly.
> No matter what you're actually testing for, there is no way you're going to
> get a TRUE result from comparing ( signed 32 bit integer > 0x7fffffff ).
Right, and chop <= (max ber_len_t)/2.3333 so the test is a no-op on
32-bit hosts. But on 64-bit hosts, chop can be an 8-byte integer
which would require the first byte in the output key to hold 10 bits:
inverse sign bit, 8 more bits (one for each chop byte), final sign bit.